Logicki zadaci

[^m00dO_oD_kOlJiBrIyA^]

Udje kroz rupu od 2 cm, ne zna izaci na vrata od 2 m?

[Beethoven's C***]

Pedofil?

[Glenn_Q]

Udje kroz rupu od 2 cm, ne zna izaci na vrata od 2 m?

muva, obad, stršljen ???

[^m00dO_oD_kOlJiBrIyA^]

Pedofil?

a-a

muva, obad, stršljen ???

MuVA.

[Hakunamatata_Pg]

E ovako imam i ja jedan zadatak za Vas...

Pošto nisam dokojan da čitam 76 strana u ovom topiću ne znam je li neko prije mene postavio ovo ali ako jeste neka odma odgovori.

U kući koja se sastoji od prizemlja i sprata, u prizemlju postoje tri prekidača koja pale tri sijalice na spratu. Pri tom kada stojite kod prekidača u prizemlju ne možete da vidite sijalice na spratu.

Kako odrediti koji prekidač u prizemlju pali koju sijalicu sijalicu na spratu ako imate pravo samo jednom da se popnete i da pogledate?

Ajmo junaci sad

[Kralj95]

E ovako imam i ja jedan zadatak za Vas...

Pošto nisam dokojan da čitam 76 strana u ovom topiću ne znam je li neko prije mene postavio ovo ali ako jeste neka odma odgovori.

U kući koja se sastoji od prizemlja i sprata, u prizemlju postoje tri prekidača koja pale tri sijalice na spratu. Pri tom kada stojite kod prekidača u prizemlju ne možete da vidite sijalice na spratu.

Kako odrediti koji prekidač u prizemlju pali koju sijalicu sijalicu na spratu ako imate pravo samo jednom da se popnete i da pogledate?

Ajmo junaci sad

Upalis prvi prekidac, sacekas 5 minuta, ugasis ga.
Onda upalis drugi prekidac i odes gore.
Prvi prekidac pali sijalicu koja je jos uvijek vruca (jer se zagrijala za 5 minuta kolko je bila upaljena), drugi prekidac pali sijalicu koja trenutno svijetli, a treci prekidac pali sijalicu koja je ugasena i hladna

[Hakunamatata_Pg]

Sjedi 5

[HipHop]

Sjecam se oceve zagonetne kad sam bio mali , Ulazi pop u ucionicu i govori, Dobro jutro 100 djaka, a oni mu odgovaraju "Nije 100 djaka, nego ovo, i jos ovoliko i polovina i cetvrtina i ucitelj sa nama i tek 100 djaka" i da cujem koliko bilo djaka, sjecam se koliko se mucio sa 10god da izracunam

[SpellStealer]

x -> broj djaka
x+x+(1/2)*x+(1/4)*x + 1 =100
2*x+(3/4)*x = 100-1
(2+3/4)*x=99
(11/4)*x=99
11*x=396
x=396/11
x=36
Jupiiii

[HipHop]

x -> broj djaka
x+x+(1/2)*x+(1/4)*x + 1 =100
2*x+(3/4)*x = 100-1
(2+3/4)*x=99
(11/4)*x=99
11*x=396
x=396/11
x=36
Jupiiii

Hhahahah tacno tako :fat:

[Recordare88]

Ako ovo nije najbolja tema na Forumu, ubijte me. A ja je tek sad otkrio... Evo da ozhivimo:

A group of people with assorted eye colors live on an island. They are all perfect logicians -- if a conclusion can be logically deduced, they will do it instantly. No one knows the color of their eyes. Every night at midnight, a ferry stops at the island. Any islanders who have figured out the color of their own eyes then leave the island, and the rest stay. Everyone can see everyone else at all times and keeps a count of the number of people they see with each eye color (excluding themselves), but they cannot otherwise communicate. Everyone on the island knows all the rules in this paragraph.

On this island there are 100 blue-eyed people, 100 brown-eyed people, and the Guru (she happens to have green eyes). So any given blue-eyed person can see 100 people with brown eyes and 99 people with blue eyes (and one with green), but that does not tell him his own eye color; as far as he knows the totals could be 101 brown and 99 blue. Or 100 brown, 99 blue, and he could have red eyes.

The Guru is allowed to speak once (let's say at noon), on one day in all their endless years on the island. Standing before the islanders, she says the following:

"I can see someone who has blue eyes."

Who leaves the island, and on what night?


There are no mirrors or reflecting surfaces, nothing dumb. It is not a trick question, and the answer is logical. It doesn't depend on tricky wording or anyone lying or guessing, and it doesn't involve people doing something silly like creating a sign language or doing genetics. The Guru is not making eye contact with anyone in particular; she's simply saying "I count at least one blue-eyed person on this island who isn't me."

And lastly, the answer is not "no one leaves."

[AvAtAr_Nk]

Ako ovo nije najbolja tema na Forumu, ubijte me. A ja je tek sad otkrio... Evo da ozhivimo:

A group of people with assorted eye colors live on an island. They are all perfect logicians -- if a conclusion can be logically deduced, they will do it instantly. No one knows the color of their eyes. Every night at midnight, a ferry stops at the island. Any islanders who have figured out the color of their own eyes then leave the island, and the rest stay. Everyone can see everyone else at all times and keeps a count of the number of people they see with each eye color (excluding themselves), but they cannot otherwise communicate. Everyone on the island knows all the rules in this paragraph.

On this island there are 100 blue-eyed people, 100 brown-eyed people, and the Guru (she happens to have green eyes). So any given blue-eyed person can see 100 people with brown eyes and 99 people with blue eyes (and one with green), but that does not tell him his own eye color; as far as he knows the totals could be 101 brown and 99 blue. Or 100 brown, 99 blue, and he could have red eyes.

The Guru is allowed to speak once (let's say at noon), on one day in all their endless years on the island. Standing before the islanders, she says the following:

"I can see someone who has blue eyes."

Who leaves the island, and on what night?


There are no mirrors or reflecting surfaces, nothing dumb. It is not a trick question, and the answer is logical. It doesn't depend on tricky wording or anyone lying or guessing, and it doesn't involve people doing something silly like creating a sign language or doing genetics. The Guru is not making eye contact with anyone in particular; she's simply saying "I count at least one blue-eyed person on this island who isn't me."

And lastly, the answer is not "no one leaves."

Promasio si temu, imas tamo podforum English only

[St.Dzonny]

a i ovaj zadatak je obradjivan u min 100 postova prije nedje na ovoj temi?

[Recordare88]

a i ovaj zadatak je obradjivan u min 100 postova prije nedje na ovoj temi?

Prastajte, nisam gledao

Evo, ova nije bila: Zivis u gradu koji ima dva frizera, koji imaju salone jedan do drugog. Hoces da se oshishash. Jedan od njih ima super modernu i urednu frizuru, a drugi razbarushenu, lose oshishanu i masnu kosu. Kod kojeg treba da podjesh?

[djeye]

Zavisi, ako šišaju sami sebe (kao ja) ili jedan drugoga

[aLaPaCha]

To nije zagonetka vec stvar izbora.

[no-mercy]

Kod ovog sto ima rascupanu kos, jer, ako ne sisa sam sebe, sisa ga ovaj zalizani sto znac da je on los frizer.

Jesam li pogodio?

[Recordare88]

Jesi. Stroll on

[Bugi]

Kod ovog sto ima rascupanu kos, jer, ako ne sisa sam sebe, sisa ga ovaj zalizani sto znac da je on los frizer.

Jesam li pogodio?

Možda ovaj jedan masni neće da konkurenciji ostavlja pare?

[Divlad]

Matematički zadatak, ali...

[An0n1mUs]

Dupla kvadratna jednacina, ajmo dalje.

[Bronx-PG]

Okolo je čupava, ima rupu, kad je navučeš topla je i udobna. Počinje na slovo P ima slovo Č i završava se na A?

[no-mercy]

Da nije pikca?

Sent from my Nexus One using Tapatalk 2

[Bronx-PG]

Da nije pikca?

Sent from my Nexus One using Tapatalk 2

Previše bi lako bilo da je to što si ti pomislio ipak razmisli malo koristiš je

[slavisa]

papuca druze kakve su ovo fore debilne